Recent content by Needhelp62

Re thought and the centre of mass is accelerating to the right so there must be friction

Are you sure there is friction? Maybe the normal force changes direction

think I've got it, if i call the original integral Q so (2-\frac{2}{y+1})Q+\frac{2}{y+1}

Thank you I get how the original integral i used now.I have two integrals with the first being twice the original and the second being \frac{2t^2}{(y+1)+t^2(y-1)}

y is just a fixed number the question says the answer to the integral is a function of y

First part of the question was to work out the integral 1/(y+cos(x)) between x=0 and x=pi/2 by using the substitution t=tan(x/2). Got this to be \frac{2}{\sqrt{y^2-1}}arctan(\sqrt{\frac{y-1}{y+1}}) The next question says HENCE find integral with the same limits of \frac{1}{(y+cos(x))^2} Ive...