Recent content by neomah

From what I learned (teaching us), Work done = the change in Ek (my bad on the first post.) So, this is what I am thinking now: W = Ek2 - Ek1 W = 1/2m(v2'2 - v1'2) and do we add the mass of the ball and the box? or just use the ball? and thanks for correcting my math, lol XD

That's actually true. Thanks. :) The aim of the experiment is to calculate P, P', Ek, and Ek'. So given the masses of the two pucks of air/spark table, mpuck1 = 356.40g and mpuck2 = 180.57g For the momentum. I got the speed = d/t. So P1 = mv =0.7(356.40) =249.5 P2 = 0.7(180.57)...

So, we still need the Work? and work done = kinetic energy and relationship of momentum and kinetic energy? if we are trying to find v, and p=mv is the equation. do we rearrange? so, v = p/m? and then do we sub it in here? Ek = 1/2mv2 then, Ek = 1/2m(p/m)2 then, Ek = 1/2m(p/m)2...

Homework Statement A ball was thrown into a box. Determine Ek, P, and throwing speed when the: mass of softball = 172.7g mass of packed box = 2,043.5g and the box moved from 0 cm to 2cm. and the spring scale that remained parallel to the floor was Ff=8N. Homework Equations Ff=\muFn Velocity...

Homework Statement Okay, we have a lab about elastic and inelastic collision, and we have to do it in an air table/spark table that generates dots (can be like ticker tapes). We have to determine Momentum (P and P') and Kinetic Energy (Ek and Ek') Please view my attachment. (' = after...