So to solve the equation $x-8 = 6x+2$ we:
Add 8 to both sides: $x = 6x+10$
Subtract 6x from both sides: $-5x = 10$
Divide both sides by -5: $x = -2$
So, substituting x = -2 into the equations give:
$4y = -2 - 8 = -10$
$2y = 3 x (-2) + 1 = -5$
So dividing -10 by 4 or -5...
Hi,
I am looking for some help on how you find the point of intersection of the following two lines:
4y = x - 8
2y = 3x + 1
Thanks for any help.
/Nichola