Recent content by nowayjose

What differentiation do you see? it would be great if you could write what you see so that i can see it as well.

Homework Statement αh=α-ε+ih ΔαH/Δα= dαH/dα = d/dα x (α-ε+ih) = 1-(dε/dα)

Homework Statement "For there to be static equilibrium of a rigid body the sum of the forces and moments must equal zero." From high school I've understood that a body in equilibrium doesn't accelerate but remains at rest or ofc in constant motion. Is the idea of static equilibrium of rigid...

I've understood everything. Thank you all for your feedback... basically when we get the indeterminate form 0/0, preliminary algebra can be used to find another fuction equal to f(x) when x≠a. When the numerator is zero, then there's obviously no limit. The only doubt i have is when the...

Yes, there are two typos. it's the limx-2 for the question itself. and when i gave an example for a numerator = 0 i don't know why i gave a wrong one. but what ever, basically what i meant was that when the denominator equals 0 it's undefined and its the same idea for when the numerator equals 0...

Homework Statement limx→2(x+2)/(x^3+8) 2. I only recently started learning calculus on my own so correct me if I'm wrong. When using direct substitution and the denominator equals 0, the limit is undefined, just like any fraction is when its denominator equals 0. However, it's limit can still...

Homework Statement Find the inverse function of f(x)= 2x + lnx 2. The attempt at a solution So usually i would start out with y= 2x+lnx (finding x terms of y) and then switch x and y... but i can't figure out how to find x. doesn't seem to be possible to factorize this... are there other...

Would you care explaining me how you multiplied out what's rooted? I know sin(sin^-1) cancel out because you add the indices, so shouldn't that leave sin x..

People sorry for the typo and for not being clear about my thought process. Bascially what i meant was: \theta = sin^{-1}x sin\theta = x If the sine angle is X, then the opposite is X and the hypotenuse 1. the adjacent side can now be calculated using pythagoras, which gives...

Thanks for the prompt reply! Sorry, and the question's undoubtedly stupid. I've used this method before and haven't happened to used any identities (or so i believe...). \theta = sin^{-1}x sin\theta = x sin = 1/X the cosine side must therefore be \sqrt{1-x^2} therefore the cosine...

Homework Statement cos(sin-1x) = \sqrt{1-x^2} Homework Equations I would assume trigonometrical identities would be used to prove this.