Recent content by NPM

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    Air Pressure and Net Force on a Door in a Tornado

    So I tried doing the problem: P=F/A Regular pressure = 1.0 x 10^5 15% decrease = 8.5 x 10^3 85000 = F/(195 x 91) = F/177.45<--- Converted to meters So I multiplied by the area: 85000 x 177.45=15,083,250 Pa And that, to me, seems like a completely ridiculous answer. Would...
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    Air Pressure and Net Force on a Door in a Tornado

    Never mind. I just realized that P=F/A would work. Whoops xP
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    Air Pressure and Net Force on a Door in a Tornado

    Homework Statement In a tornado, the pressure can be 15 percent below normal atmospheric pressure. Suppose that a tornado occurred outside a door that is 195 cm high and 91 cm wide. What net force would be exerted on the door by a sudden 15 percent drop in normal atmospheric pressure? In what...
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