Recent content by ny_aish

thank you sooooooooooooooooooo much! now it feels that the problem was so easy but i fried my brain over it! I appreciate your help and patience :)

I apologize for the misunderstandings. So when the vehicle drives up a 27 degree incline, the 3 forces at play are the GRAVITY, THE FORCE * cos27 , THE COEFFICIENT which will be negative *** And power is directly proportional to Force and Velocity ***In other words, I find the Force by drawing a...

this is similar to wat i made

thats -Cof cos27, m, g. but since we r calculating Power why don't i need time or distance?

which are the m, g, Cofcos 27 ... correct?

A motorcycle (mass of cycle plus rider = 2.5 102 kg) is traveling at a steady speed of 15 m/s. The force of air resistance acting on the cycle and rider is 1.5 102 N. Find the power necessary to sustain this speed under the following conditions. b) the road is sloped upward at 27° with...

thanx

so its (6.67*10^-11)(1.06*10^24)(6000) / (4.10*10^6)^2 which is = 2.523569 * 10^4 which is same as 25235.69 ... can you please just confirm it for me? I have only 1 chance left, and I dnt want to lose points. Thanks

ohhhhhh

A satellite has a mass of 6000 kg and is in a circular orbit 4.40 10^5 m above the surface of a planet. The period of the orbit is two hours. The radius of the planet is 4.10 10^6 m. What is the true weight of the satellite when it is at rest on the planet's surface? m=6000kg t=7200 s...

So N = mg

A motorcycle has a constant speed of 30.0 m/s as it passes over the top of a hill whose radius of curvature is 134 m. The mass of the motorcycle and driver is 333 kg. a)Find the magnitude of the centripetal force that acts on the cycle. (I found the Centripetal force by Fc=mv^2/r which is...

yesssss! that's right tooo, for Acceleration i used Delta V/Delta T. Thanks :)

my method was right but I needed to convert Grams to Kg, Thanks though!

hmmmmmm...let me give it a shot