Recent content by nyoo

Um, I knew there was going to be one last thing. There always is. Could you please show me how you arrived at that 0.6 - 0.8 range for discharge coefficient? Thanks again.

Thank you, all, for your insights. I now have an answer, and that's marvellous. But, at some quite large effort to yourselves, you have also provided me with the tools so that if the circumstances of my design change, I can accommodate them. (Or if that neighbour down the street, whose back...

Thank you for your immense effort here. Be assured that I shall use this several times, and will given credit when I share it with others. I assume the idea is to first get rho out of the equations? So we'd work in metric? ρ, the density of water = 1 kg/m^3 p(0), the inlet pressure =...

Ohm's Law: volts (E) = amps (I) * ohms (R) Watts Law: watts (P) = amps (I) * volts (E). A useful derivation is: P = (I^2) * R = current squared * resistance Let's try a 100-watt lightbulb. And 120 VAC. AC: 100 watts = .833^2 amps * 144 ohms 120 volts = .833 amps * 144 ohms...

Thanks for the practical advice. It's a good idea: I will experiment using PVC, and expect uneven spacings. If only I could get clear in my head some of the principles at work. Like yourself, I expect the water pressure to reduce near the capped ends, furthest away from the tee. But...

"shower head" for feeding water onto a solar thermal panel Homework Statement The question is homework to me, but I haven't actually seen formal physics classwork since college, 41 years ago. Please advise if this question is misplaced. I'm building a "shower head" to trickle or spray...