Recent content by NZS92

I literally have no idea, tried log, ln, e^x, my first work: 7.3^(x-1)+5=3^(x+1) log_(3) (7.3^(x-1)+5)=x+1 e^(log_3 (7.3^(x-1)+5) / e^x = e (7.3^(x-1)+5)/e^x =e 7.3^(x-1)+5= ee^x 7.3^(x-1) -ee^x=-5 my second work, 7.3^(x-1)=3^(x+1)-5 (x-1)log(73/10)=log(3^(x+1)-5) xlog(73/10)-log(73/10) =...

Solve for x, (73/10)^(x-1)+5 - 3^(x+1)=0

Your part "a" isn't correct it says you need to find the acceleration not velocity, the velocity you find also incorrect.

Homework Statement A potential difference of 24 kV maintains a downward-directed electric field between two horizontal parallel plates separated by 1.8 cm. Find the charge on an oil droplet of mass 2.2 x 10^-13 kg that remains stationary in the field between the plates. Homework Equations...