Recent content by Oloria

But I don't know how to write down the elastic forse. Could you help me?

F = \frac{k_e Qq}{R^2}? I thought the sphere will repel a hoop so it will be impossible to start surpassing (being so close of two objects). (When the sphere is in the hoop they have to repel each other so the hoop will be larger).

Very sad. Transcience of human life... It's something to think about. Do the most important for us right now, cause in a while there could not be the time...

I didn't ask. I just mentioned it because of my psyche. Never mind. I suppose there are many people that study (or studied) Physics. Why did you choose Physics, folks?

Q and -q, am I right? And I don't know what to do next. Can you help me, please?

I have got one question... Why do you study Physics? I guess the reason can't be money :D

Repel? I thought there should be Q and -q so they attract each other. I don't understand :( F = \frac{k_e Qq}{R^2} I guess the distance between midpoints of these two objects is R. q is the charge on the sphere.

Did you draw the situation? In my opinion in Vx should be sin, and Vy cos (pointing in a direction θ = 26° East of North). v = \sqrt{(v_w - v_x)^2 + v_y^2} (the Pythagorean theorem) v_w - speed of wind And then d=vt I got 135,45km and I think it's a fault of approximation.

Hi tiny-tim :smile: I think the electrici force got to be bacbalanced by a force connected with resilience. I think F~ψ but I don't know how to write it down properly. I don't understand why you used "-P" and I don't know what answer you expect (I have already mentioned Coulomb's law).

Homework Statement What minimal charge should have a sphere of radius R to surpass a thin circular hoop of radius r that is uniformly distributed with the charge Q and made from resilient elastic. The elastic modulus (of resilience) is \Psi. R>r Homework Equations Coulomb's law.The Attempt at...

I know such basic informations. It is hard to explain you the situation, you don't understand. I think I found the solution but I need a little time to proove it correctly.

Yes, but it's not what I was thinking about. "each lateral edge of a pyramid can be perpendicular to one of base's edge" The base is a four sided figure. It doesn't mean that perpendicular straight lines has to cross themselves like it is required on a facet. Though, they should be...

I don't care about the method. I just want to know. It is not my homework.

Hi, I wonder if each lateral edge of a pyramid can be perpendicular to one of base's edge? The base is a tetragon. (If it is possible what a tetragon should it be and if it is not why) Can you help me, please? This is my first post so I want you to be understanding :shy: