Okay i got how to do x1/3 by using the difference of cubes and x1/2 by difference of squares but I am stuck on what todo with x1/6.
what i tried so far
F(x)= [ f(x+h) - f(x) ]/ h
a2= (x+h)1/6
b2= (x)1/6
so I eventually got to
[a6-b6]/h[a4+a2b2+b4
I used the difference of cubes with this or...