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Recent content by omg4cards
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Calc 2 - Taylor Expansion Series of x^(1/2)
I left out the signs to simplify and becaus I already identified the pattern w/ (-1)^(n+1)... so if i kept the signs in, the #'s in the numerator would be (1, -1*1, -3*-1*1, -5*-3*-1*1)
omg4cards
Post #4
Dec 14, 2009
Forum:
Calculus and Beyond Homework Help
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Calc 2 - Taylor Expansion Series of x^(1/2)
I have no idea why it looks like that...
omg4cards
Post #2
Dec 13, 2009
Forum:
Calculus and Beyond Homework Help
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Calc 2 - Taylor Expansion Series of x^(1/2)
Homework Statement f(x) = \sqrt{x}, a = 4 Homework Equations f(x) = \sumf^{n}(a)/n! (x-a)^{n} The Attempt at a Solution f(x) = x^{1/2} f^{'}(x) = \frac{1}{2}x^{1/2} f^{2}(x) = -\frac{1}{2}*\frac{1}{2}x^{-3/2} f^{3}(x) = \frac{1}{2}*\frac{1}{2}*\frac{3}{2}x^{-5/2} f^{4}(x) =...
omg4cards
Thread
Dec 13, 2009
Calc 2
Expansion
Series
Taylor
Taylor expansion
Replies: 5
Forum:
Calculus and Beyond Homework Help
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