Recent content by omwattie

(0,1,-1)

I found (0,-12)

I have -12x^2-12

I believe the second derivative

I figured out the where f (x) is increasing and decreasing but I don't know the concave up and concave down

sqrt(3),-sqrt(3)

There is no critical value(s)

Okay what I did before I tried solving it with the quotient rule which was wrong, so I used the product rule which gives me the; F'(x) = -4x^3-12x - - - Updated - - - Sorry for the confusion

yeah but the equation are multiplying not dividing.

I used the quotient rules which gives me (4-x^2)(2x)-(x^2+10)(-2x)/(4-x^2)^2=28x/(4-x^2)^2 CV=-28,-2,0,2,16 I also did it another way by multiplied the two equations but the answers look weird

Sure I have no problem, well first of all you find the derivative of the originally equation, which I did but the answers is wrong.

Yes curve sketching

Suppose that f(x) = (x^2 + 10)(4 - x^2). (A) Find all critical values of f.Critical value(s) = (B) Use interval notation to indicate where f(x) is increasing. Increasing: = (C) Use interval notation to indicate where f(x) is decreasing. Decreasing: = D) Find the x-coordinates of all local...