Recent content by Ornella
-
Graduate Converting kW/h to kWh for Optimizing Fuel Cell Ramp-Up
I was trying to obtain the energy during the actual time of ramp-up. But I solved my problem. Thanks anyways.- Ornella
- Post #12
- Forum: Thermodynamics
-
Graduate Converting kW/h to kWh for Optimizing Fuel Cell Ramp-Up
I actually found out the time for ramp up to be 25 min. 0.04/min * 60 min/h * 58 kW = 139.9 kW/h 58.3 kW / 139.92 = 0.42 h = 25 min Then I applied the method as you said. 0.5 * 58.3 * 0.42 = 12.5 kWh Thanks again!- Ornella
- Post #9
- Forum: Thermodynamics
-
Graduate Converting kW/h to kWh for Optimizing Fuel Cell Ramp-Up
Thank you very much! That's what I was looking for!- Ornella
- Post #8
- Forum: Thermodynamics
-
Graduate Converting kW/h to kWh for Optimizing Fuel Cell Ramp-Up
the energy during the ramp up of my fuel cell- Ornella
- Post #7
- Forum: Thermodynamics
-
Graduate Converting kW/h to kWh for Optimizing Fuel Cell Ramp-Up
The power is actually constant. I am trying to expand the simulation per every hour of the year. Is it still wrong?- Ornella
- Post #3
- Forum: Thermodynamics
-
Graduate Converting kW/h to kWh for Optimizing Fuel Cell Ramp-Up
Hi everyone, I am working on a mathematical optimization model for a fuel cell. Currently I am facing a problem with the ramp-up of the cell. I have a modulation ramp of 4% of the nominal power (58.3 kW) per minute. My constraint in the model has to be in kWh (I have to precise that my...- Ornella
- Thread
- Constraints Energy Optimization Power Unit conversion
- Replies: 11
- Forum: Thermodynamics