Recent content by OSUstudent

Thank you for your reply! I am looking for a formula that i could use to calculate where the center of the circle is based on the known diameter and a single point that resides in the red area. Sorry i should have meant to say in the original post that i was looking for a simple formula.

Hello! I have an application where I need to find the center of a circle where I am having trouble coming up with a simple way to do this. The diameter of the circle is known and i want to be able to determine the location of it where only a portion of the circle is known. (see the image...

Ok i will try this again...Let say I have an empty plastic bottle and I want to fill it with water to see how many grams it weighs. So I do this at 70deg F. and 14.7psi atmosphere pressure(no cap) take my measurement and I get 500grams...Now I record my measurement and empty the bottle. I...

Doesn't it change the volume? If I fill a bottle with water at 22degC and atm. Pressure at 14.7 psi, say I have 500grams of water in the container. Then I empty the container change pressue to 15.7psi and refill it will it remain the same. Say a plastic bottle.

The mass of the water

Does anyone know where or how I could calculate the change during pressure changes?

I see where the confusion was I guess i didnt explain what I was trying to do in my first point. But you have answered what I was looking for. Thank you to everyone who replied!

using the density table I would assume that If i had 500ml of water in a bottle at 4C then I would have 500 X 0.9999720= 499.986 grams of water at 22C I would have 500 X .9977735 = 498.886775 grams of water Does this sound correct?

Yes I am clear on this but if the temperature changes in the water will the weight change? If I have 500grams of water at 70F do I still have 500 grams at 90F?

I have something I need cleared up and looking for some calculation help. I know that water changes density with temperature but does it change due to lack of gravity when the moon is close? So to clear things up I guess I need to know what and how thoes changes will affect the weight of water...