Recent content by Ozkan Suna

Not guessing, it's confusion. The average of -2 and 3 is: -2 + 3 / 2 = 1/2

a?

1.5 a right?

Oh, so we have to split it up to 2a/2 = a and 3a/2 = 1.5a?

1) We have a single force at the end of the beam. So I say the force multiplied with the total lenght. 2) From the left side of the beam to the half we have distributed load. So I want to find where the single force attacks, and that is on the half on the beam, right? Sorry for my bad English!

So if I want the moment ΣMz = 0; Dy * 6a - P*10a - p*5a*2,5a = 0 and then isolate Dy and substitute it in ΣFy = 0; By + Dy = 5ap + P??

'' Point of my choice has to be zero '' Does it mean I have to add a charnier? Sorry for the confusion

The question is: How do I find all the reactions? I haven't worked with a similar problem before, so I'm kinda confused. Hope someone will help! Thanks from now.