Recent content by ozni

How does this end up +? Can't work out steps.

Okay, then follow through on what neilparker62 suggested?

*note the time for both impulses is constant as well as the force applied Because we know that masses are irrelevant to the answer we can also substitute in values for them. I also made the time one second so the values would be easy So assuming mass of cart one is 10kg we find the force to be...

I see what I need to do. Ft is equal to both equations its the combining into one is the issue

Set them equal?

Great - such useful extra info! I'm not 100 percent with plugging in as I'm trying to fill gaps in with my algebra - plugging into 3rd equation?

Thankyou for that. So its fractioned ( a quarter and a sixth). You could use decimels?

Thanks - getting there. Could you explain I'm home schooled so any assistance is greatly appreciated.

They are subjected to the same pulse when joined together as they were when they were not joined together. I just can't seem to relate it mathematical

Homework Statement A railway locomotive pushed a stationary wagon and accelerated to 4ms. Did the same to another wagon with same force and time and accelerated it to 6ms. The two now stationary wagons are bow locked together and the same impulse force is applied to the wagons to move them...