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Chemistry Derive an expression for mean free path from survival eqn exp(-x/λ)
I was able to get the expression of probability P = ##e^{-x/\lambda}##. I followed the approach that the probability of no collision over ##f(x+dx) = f(x)(1-\frac{dx}{\lambda})## then expanded LHS using Taylor series. Then by taking the first two terms and neglecting the higher order terms, I...- P4Penguin
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- Forum: Biology and Chemistry Homework Help
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Chemistry Derive an expression for mean free path from survival eqn exp(-x/λ)
If the distance between the centres of two molecules is σ, then imagining a a cylinder with radius σ the number of molecules can be given by πσ²cn where c = average velocity. So mean free path can be given by λ = c/πσ²cn = 1/nπσ². But do I derive it from exp(-x/λ)?- P4Penguin
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- Derive Expression Mean Mean free path Path
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- Forum: Biology and Chemistry Homework Help