Recent content by pesslovany

Oh yeah, I forgot to write, that I am supposed to do it for the conductor. Dont really know what am I actually supposed to do, because I don't think Its possible to calculate it for the inside...

Thank you... I have got one supplementary: "Would the E in the shell be also 0 if the point charge wouldn't be exactly in the middle?" It should be, but there is a problem calculating \vec{E}\cdot\vec{n} = |\vec{E}|\cdot|\vec{n}|\cdot cos(\alpha) because the angles are all different, so I have...

Ok, so outside the conductor it should be : E = \frac{1}{4\pi\epsilon}\cdot\frac{Q}{r^2} Q will be same as inside the conductor. And in the shell I think it will look like this: E = \frac{1}{4\pi\epsilon}\cdot\frac{-Q_-+Q_+}{r^2} = 0

Firstly I appologize, that I am not native english speaker and I don't study physics(but cybernetics we are getting just some general knowledge about physics), but hopeffuly I will write this right. Homework Statement We know that inside of a conductive object is protected from influence of...