do I just use k=(-.883015943)/m ?
i tried doing that and this is what happened
ln(78-72)=((-.883015943)/m)*(m+30)+C
so it becomes
1.791759469=-.883015943+30+c ?
or would it be
1.791759469=(-.883015943)*(m+30)+C
or would the 30 multiply to the -.883015943?
like i can never...
ok well see through me trying to do all of this this was the problem, i don't know how to solve for both variables, i feel like itll end up being this after subtracting c from ln(83-72)
-.883015943= k
-----------
m
or
-.883015943= m
-----------
k
(m and k are being...
This still makes no sense this is what I tried and got stuck at:
ln|98.6-72|=k*0+C
so k and 0 cancel and i get
3.280911216=C
so then since I don't know M (which i think you originally used x) but from going from 908 to 938 and there being a 5 degree drop I assumed that's constant and...
This still makes no sense this is what I tried and got stuck at:
ln|98.6-72|=k*0+C
so k and 0 cancel and i get
3.280911216=C
so then since I don't know M (which i think you originally used x) but from going from 908 to 938 and there being a 5 degree drop I assumed that's constant and...
I'm going to write this up the same way my teacher gave me the sheet
Homework Statement
At 9am on october 19, 2009 a body was found in room 327 at University Center. The room is kept at a constant temperature of 72 degrees. The medical examiner was called and he arrived in eight minutes...
I'm going to write this up the same way my teacher gave me the sheet
Homework Statement
At 9am on october 19, 2009 a body was found in room 327 at University Center. The room is kept at a constant temperature of 72 degrees. The medical examiner was called and he arrived in eight minutes...