Recent content by phoenixcat

Haha, accidentally thought for a second(more than a few seconds) finding the Y intercept was finding the y value of the tp (Giggle) thanks for the help, will try applying this to future situations!

I end up with y=5/3x^2 -95/3x +470/3.. I think it should work, but I was also given a not-to-scale diagram with the question, and it shows the TP to have a smaller y value, the TP is above the x-axis and below 10, it's confusing, hmm

Hello, I am supposed to find the equation of a parabola with the points (8,10)(11,10)(10,20/3). I have tried putting these values into y=ax^2+bx+c, but get different answers each time, like c=-160, which is not right! A step by step explanation would be greatly appreciated, as I am very unsure...