Recent content by PhrozenN

Oh, I did the calculations wrong I got a = 4.48 so now it's 1.077 The equations are set properly right? Thanks btw

I = mR^2 since its a rim-like thingy T1R - T2R = I(a/R) m1(g-a)R - m2(g+a)R = mRa a = 4.44 m/s^2 x = vt + 0.5at^2 t = 1.082

A 1.2 kg mass and a 7.1 kg mass are connected by a massless string over a pulley that is in the shape of a bicycle wheel (all mass is concentrated at the rim) having a radius 0.25 m and mass 4.6 kg. Determine the time for the masses to move 2.6 m starting from rest. A. 2.714 sec B. 0.223...