Recent content by Physicsboi123

Oh, I understand, so the spring oscillates for a while before coming to rest. I understand that KE is greatest at equilibrium and that energy, but the question didn't mention that the stone is at rest in equilibrium position, which is mg=kx. How would you deduce that v=0 when x=mg/k, an energy...

I suppose it would slowly descend to resting place and stop? I know you have to use Fnet=0 to calculate k, but wouldn't that just be where acceleration is 0, not velocity?

Using conservation of energy, 0.5kx^2=mgh=mgx 0.5kx=mg 0.5kx=mg, x=0.15, m=9, g= 9.8 So isn't it k= 1176N/m? For this problem, I understand that you can't use conservation of energy, but why? There is gravitational potential energy at the top and spring elastic energy at the bottom, and no...