Recent content by physicsboy007

Thank you :)

but that is not the right answer, it is 6.9 according to my answer sheet

I uploaded a picture above, please look. There is a 20 N force from the right and tension to the left

Why is it not: Fnet= T-13.728N=ma There is still tension pulling the block

Is it not F-T-o.16(m1+m2)(g)-0.16(m1)(g)=2a ? 20-T-0.16(3kg)(9.8) - 0.16(1)(9.8)=2a

I've included those in my equation already... themagnitude of the friction force developed between the 2kg block and the floor? = o.16(m1+m2)(g) the magnitude of the friction force developed between the 1kg block and the 2kg block? =0.16(m1)(g) 2kg block has 1 kg on top so I added...

b]1. Homework Statement [/b] There is a 1kg block on top of a 2 kg block. The 2 kg block A rope pulls on the lower block with a tension force of 20N. The coefficient of kinetic friction between the lower block and the surface is 0.16. The coefficient of kinetic friction between the lower...