Recent content by physicsguy98

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    Find f ' (2) for Simple Derivatives: g(2)=3, g ' (2)=-2, h(2)=-1, h ' (2)=4"

    I tried using lim(x->c) of f(x) - f(c) / x-c but i end up with lim (x->c) of (2g(x) + h(x) -5)/(x-2) for part (a) and i don't know where to go from there
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    Find f ' (2) for Simple Derivatives: g(2)=3, g ' (2)=-2, h(2)=-1, h ' (2)=4"

    Find f ' (2) given the following. g(2) = 3 , g ' (2) = -2 h(2) = -1 , h ' (2) = 4 a. f(x) = 2g(x) + h(x) b. f(x) = g(x) / h(x) c. f(x) = 4 - h(x) d. f(x) = g(x)*h(x)
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    Field Goal Projectile Problem: Time to Score!

    A place kicker attempts a field goal, giving the ball an initial velocity of 27.0 m/s at an angle of 30.0° with the level field. The uprights are 35 m from the point at which the ball is kicked and the horizontal bar is 4.0 m from the ground. At what time after the kick will the ball pass the...
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    Radial and Tangential Acceleration Question

    A ball tied to the end of a string 0.5 m in length swings in a vertical circle under the influence of gravity. When the string makes an angle of 20 degrees with the vertical, the ball has a speed of 1.5 m/s. Find the tangential component of acceleration at this instant. Help! Tangential...
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