Recent content by PhysicsNewbie321

my mistake.. its ohms. thanks for all your help !

e) 2A f) 2a+1a = 3A g) 1/6 + 1/3 = 1/2 = 2A? @cnh1995

a i see constant pd thanks

d) v=? r=3ohm i=2a(6/3) v=ir 2x3 = 6V? e)2A? but how come can both be 6V when its a 6V battery?

Thanks that's a question done. For the next problem, a) 1.5x4 = 6V b) V? R=6ohm I= 1? (v/ohm,6/6) 6x1=6V? c) 1A? thanks a lot man

for d) is it 6V + 2V = 8V? e) each cell has 2v?

for b) 2A c) v=Ir 2x1=2volts

thanks

2A?

series same current

its connected in series meaning voltage is divided among components. V - volts , I - current. I don't know the volts of the battery

I don't know if I can work out b) without any given volts in the 2nd 1ohm resistor

Homework Statement Homework Equations Ohm's Law : V = IR, Eel = VIt , Vt=ItRt , Q=It The Attempt at a Solution I tried to do the first question letter a I=? I= V/R R=3 ohms I= 6/3 V=6V I=2A[/B] i don't know how to continue the others :/

Is it because as current goes to the voltmeter and ammeter it loses "energy" meaning the bulb won't light up?

Voltmeter to measure voltage between two points. Ammter to measure current in a circuit