Recent content by pilot12

@BvU I figured it out, the masses cancel out and then you can solve it. Appreciate your help!

That the kinetic friction is equal to the Fnx? @berkeman

@berkeman I believe it is saying it is sliding down at a constant speed. If it wasn’t, I think it would be an acceleration

Sorry I did not know that @BvU , I was trying to use mgh + 1/2mv^2 - (s1+s2)u m g=0 h= 1.18sin(28.1) = .55579

When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 2.19 m/s. The mass stops a distance S2 = 2.1 m along the level part of the slide. The distance S1 = 1.18 m and the angle θ = 28.10°. Calculate the coefficient of kinetic friction for the mass on...