Recent content by pjwasz

Ah, I see. So what I was doing was calculated the flux due to the magnetic field of the big loop, but through the big loop itself. Instead, I need to calculate the flux due to the magnetic field of the big loop, but through the small loop. ...Good news, that worked! Thanks guys, I get what I...

Homework Statement A small, 1.60-mm-diameter circular loop with R = 1.40×10−2Ω is at the center of a large 120-mm-diameter circular loop. Both loops lie in the same plane. The current in the outer loop changes from 1 A to -1 A in 8.00×10−2 s. What is the induced current in the inner...