So I plug in my found Velocity. into the Vf=Vi+at equation. I know Vi has to be 0 or at least assumed to be. Acceleration is given to me;9.8 m/s^2. and I have the velocity.
Disregarding the sign. 18.93=0+(9.8)t therefore t = 1.93 seconds
Plug that into the distance equation Yf =...
Homework Statement
A tuning forking vibrates at 512Hz falls from rest and accelerates at 9.80m/s^2. How far below the point of release is the tuning fork when waves of the frequency 485Hz reach the release point? Take the sound of sound in air to be 340m/s.
Homework Equations...