Ok, since 4 amps is flowing through r1, then r2 must have 4 amps, but the 15volts must be split across the 2 sections as the incoming voltage must equal the outgoing. So I would get a parallel circuit. 1/x (since r1 and r2 equal) + 1/200+150 so 1/x +1/350=1/r then I'd multiply that by 4 to get...
From what I understand is that you can sum up R3 and R4 to get 350 ohms
Then you can can a parallel circuit with the missing resistors, 4amp and the new 350 ohm resistor and that's about it.
My textbook says the answer is 55 ohms for the resistors and the current is 0.073 but I got 3.75 ohms...