Recent content by pumpkin88

is this correct so far? 9 \int tan^{3} \theta \sqrt{ sec ^{2} \theta

would d(theta) be 3sec(theta)tan(theta) ?

so would it be 3tan^3 theta times the sq rt of 3tan^2theta +9?

yeah. its the integral of x^3 times the sqrt of x^2 + 9

I'm very unsure on how to do this equation... Someone PLEASE HELP! \intx^{3}\sqrt{}x^{2}+9 i do know that if you... let x = 3sec \vartheta dx = 3 sec \vartheta tan \vartheta du