Thank you!
The maths department screwed up then because the question asked to verify that C=2 but with the above integration it equals 3... So they omitted one result... >.<
Heya...
I just stumbled upon this integral while doing ODEs...
∫x*(x-2)-2dx
I used integration by parts
u=x
du/dx=1
dv/dx=(x-2)-2
v=-(x-2)-1
Thus
∫x*(x-2)-2dx=-x(x-2)-1-∫1*-(x-2)-1dx=-x*(x-2)-1+ln(x-2)+C
Now... I don't see anything wrong with this...
But every single online integration...