Recent content by rafay233

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    Find the Centripetal Acceleration at 2.5m from a Rotating Platform

    K sorry for being a noob, I thought it would be better if I made another post instead of editing the other one.
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    Find the Centripetal Acceleration at 2.5m from a Rotating Platform

    Okay guys I figured this out, but don't know why this works. 4.9m/s*1/4.3m = 1.14s 1.14*2.5= 2.84m/s (2.84m/s)^2/2.5m = 3.246 = centripetal acceleration the answer is 3.3m/s Btw I am not doing this to bump the thread, that is if it's possible.
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    Find the Centripetal Acceleration at 2.5m from a Rotating Platform

    disregard that message please. i fixed the first post
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    Find the Centripetal Acceleration at 2.5m from a Rotating Platform

    uhh guys i don't know why it looks like that. Only read the first three stuff please. Thank you
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    Find the Centripetal Acceleration at 2.5m from a Rotating Platform

    Homework Statement A person is on a horizontal rotating platform at a distance of 4.3 m from its centre. This preson experiences a centripetal acceleration of 56m/s^2. What is the centripetal acceleration is experienced by another person who is at a distance of 2.5 m from the centre of the...
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    Question: What is the slope of the curve y= (1/x-1) at x=2?

    could you guys tell me what you are using to make the fractions look like that? So no one gets confused?
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    Question: What is the slope of the curve y= (1/x-1) at x=2?

    Homework Statement Question: Find the slope of the curve at the indicated point. y= (1/x-1) at x=2 Homework Equations Don't know what relevant questions mean. The Attempt at a Solution (y(x+h) - y(x))/(x+h)-h ( (1/x-1 + h) - (1/x-1) )/h ( (1/2-1 + h) - (1/2-1) )/h ( (1+h) -...
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