Recent content by rattanjot14

First assume our field is infinite, like R or C. The difference between two polynomials is a polynomial, so f−g is a polynomial. Since f(x)=g(x) for all x, this means that f−g have infinitely many zeros, whence f−g=0. Now, for Z/pZ , p prime, we have x^p−a=x−a, since x^p=x

Homework Statement Let a and b be integers and m an integer >1 Evaluate [b/m] + [(b+a)/m]+ [(b+2a)/m]+ [(b+3a)/m]+ [(b+4a)/m]+ [(b+5a)/m]+...+ [(b+(m-1)a)/m] Homework Equations The Attempt at a Solution i tried to use hermite identity. [x] + [x + 1/n] + [x + 2/n] +...+ [x +...

We can say it is not an even function ..then how to prove that it is an odd function.

Homework Statement 1) f(x+1)=f(x)+1 2) f(x^2) =(f(x))^2 let a function real to real satisfy the above statements then prove whether the fuction is odd or even. Homework Equations The Attempt at a Solution using the 2) we get 1) f(0) = 0,1 2) f(1) = 0,1...

maximum angle is sin inverse (2√2/3) ..is it correct now?

is that correct?

answer is coming that 8/9≥(sinθ)^2

if d is less than or equal to zero.

typing error it is . the actual it is (u^2)t^2 + [(g^2)(t^4)/4] - (usinθ)gt^3.

r^2 = (u^2)t + (g^2)(t^4) - (usinθ)gt^3 differentiating it and putting it equal to 0 we get (gt)^2 -3usinθgt +2u^2 =0 so t = (3usinθ ± √9u^2sin^2θ-8u^2)/20 and also this time ≤2usinθ/g (total time of flight)] solving this i don't get the answer...i was getting that because of an error. now...

thnx answer is coming sin inverse 1/u

so is it correct to assume it constant..?

only angle of projection for which the position vector always increases..

but we had to find the maximum angle of projection..

i have a doubt when i differentiate it wrt to time i assume that theta is constant. can i do that..??