Well I picked the ball in the bottom left corner, and found that the vector components of the force the ball to the right of it exerts on it is (2.668 x 10^-8, 0).
The force the top ball exerts on the bottom left corner would have vector components (2.668 * 10^-8cos(60), 2.668 * 10^-8sin(60))...
3 10 kg spheres are located at the corners of a equilateral triangle of sides .5m. Calculate the magnitude of the total gravitational force exerted on one sphere by the other two.
I used G = 6.67 x 10^-11.
The answer I got was 4.62 x 10 ^-8. Can anyone confirm if this is correct, or explain how...