Recent content by rbsann

Yes that was my input mistake, the correct input is (x^2-a^2)^2 ( sorry for bad input) Yes i know that in thesis i am not actually ignoring the charge sign when i draw the field lines, since the negative charges point towards themselves from the observational point;- and positive charges point...

Sorry about not using the template! Next time i will use it. The calculations are fine. It seems that if i input both charge as if they were negative: E1=-q/(x-a)^2 E2=-q/(x+a)^2 i get the correct answer. That makes sense in a vector sense (both electric field lines are pointing along the -i...

Hello all, i am having a hard time with EM, specially with the most simple concepts that i don't seem to grasp at all and the simple exercises that should be quite simple to solve. So the question is. ( i will omit the constant (1/4pieo) for practice sake When i calculate the eletric field...