Recent content by reflex

I want the coefficients to be in basis B, not E. So I guess the solution provided above does that, since inputting [1 0 0]' (using B basis, this is u) gives me back [0 2 0] (which is 2v in B basis). The question was: "Find the matrix D in the B coordinate system". Unfortunately it does not...

I don't know exactly what you are referring to when you say component, but here is what I meant: The output from my original(incorrect) matrix was the B vectors in the standard basis. So to get the output of [4 10 0]' (2v in standard), I would need to multiply B*D*inverse(b) by the vector u...

Aha! Thank you very much, that makes much more sense than what I was doing. The output should be what mine was in standard, not B! Thank you very much.

@LaneDance - I got the matrix by having D= [ D(u) D(v) D(w) ] . Basically I'm asking if that is the correct method. Thanks!

@jbunii - Since v is in basis B, I just doubled v to get 2v. Does that make sense? @LaneDance - When you multiply D times [1 0 0] (only as a vector) you get the first column of D, which I thought was 2v. So it does if I'm correct about 2v..

Hi all, So this question is fairly basic, but I want to be certain I have the right idea before I do the other parts (asks about it in standard basis etc). It's a book question: Homework Statement Here are the vectors : u=[ 1 2 0] v=[2 5 0] w=[1 1 1] This forms a basis B of R3...