Recent content by regan1

if not, doesn't it violate Newton's third law of motion. to be the upward pulling force of the road greater there must be other external force.

while banking the car in a curved road from where does the car get the force to balance it's weight and force to balance it's centrifugal force. As far as i know that force is given by the reaction force of the car's weight itself. and when you divide the reaction force into it's component...

Is not R the reaction force and how can Reaction force be greater than the weight of the car ? In my opinion the maximum value that R can have is equal to the weight of the car. But since it is a slanted surface it is always less than mg

how can rcosθ in a banked road be equal to mg; since r is equal to normal reaction which is equal to mgcosθ. rcos is even smaller than r. so mg>mgcosθ mgcosθ=r r>rcosθ so mg>rcosθ then how can mg=rcos when banking in curved road?