Recent content by RichFoster

Ahhhh. TY for the link. Edit (for your edit): I did place them opposite. With the info you provided I can always add a iron backer if needed, although there will still be a ~1/4" gap between magnet end and iron backer plate. These 1/2 x 1/2 N52's are decently strong w/o making the horseshoe...

I could add steel over my AL bar (over the magnets?? you mean on the opposite side?), but that's more work. And... I don't need "more" force, just asking if flipping the polarity of the two (relative to each other) makes them pull to the iron with more force? As-is in my pic, it's basically...

Forget the "tool" part, I just want to stick this 3/4 x 3/4 AL bar to a hunk of flat iron. Two magnets are in the AL bar as the pic shows. Which orientation of the two magnets creates more holding force of this bar to the iron?

Sure, pic attached. Very simple. Only one side holds onto the press, the exposed end of the magnets, etc. The bore is only 1/2" deep in a 3/4" AL bar, etc. But see, I can orient the magnets in same polar direction, or have one flipped. Does having one magnet N and one magnet S attached to iron...

Magnetic fields coupling question. I had to make a small tool holder for my drill press, it hangs on side of press using N52 cylinder magnets. The holder is 4" long x 3/4 x 3/4" AL bar. With a spacing of 3", two 1/2" holes are bored to accept the 1/2 x 1/2 N52's, which will be epoxied in. I...

It's understood all that you say here. My comments: 1) I am proving my assertion in terms of position and time by looking for any period of time where position has not changed. Yes, time does not stop, and for any arbitrary time we only 'see' a specific position, never a change of position. Less...

(1) I am taking no measurements, purely the simple math on paper. (2) I don't yet know that the particle is in continuous motion, I am trying to prove that is it. Saying I am observing a continuously moving particle while at the same time trying to prove that it is continuously moving is a...

Mass has no motion - The position remains constant for any arbitrary time period. If it never changes position then it has no motion.

By way of the math. Does the math I have shown not prove there is continuous motion even when there is an observation at some finite time where V=0?

Why is that mind-boggling? Sure, for some time t0 that specific point has V vector where only one of it's two components =0, but for some arbitrary small t, t1 = t0+t, at t1 the V vector of that moving point on wheel once again has two components. The V vector was and never is zero, even if the...

Good stuff. The context is "motion". Does the motion of the bar ever stop its' motion? To have "stopped motion" we need to observe (prove) any dt (an arbitrary period of time) where change in position remains zero. Staying in your chair for a period of 10min is "no motion", only when you change...

There's no connecting rod in the pic. Yeah, sorry, just much faster to != vs having to click the gui button for symbol and then click a symbol. I did not think != (not equal to) would be confusing vs ≠, I guess programming math has given me some habits that do not map 100% to other notation...

I am using dx loosely here just for math purposes. I suppose dy matches the pic better. In general, dy/dt describes the motion. I mean dt as in any change in time will describe the start and end positions X0 and X1, whereby dx is the change in position X1-X0 So, the instantaneous views (some...

And then I look at this by looking at the journal itself. The journal never stops moving (a constant 1rpm), and if the bar cannot decouple from that journal movement, then how can the bar stop moving?

Agreed, but if I (you, anyone) choose any dt !=0 , whether it be up to V=0, across V=0, or after V=0, there is no dt that I can find where dx=0. If it is truly "stopped motion" when V=0, then for how long is it stopped there? If it's not there at V=0 for any period of time (dt) then is it truly...