Recent content by Rigbee

I tried your method with this equation: (x-3y)^2 - (y-x)^2 step one [(x-3y) + (y-x)] [(x-3y) - (y-x)] step two (x-3y-y+x) (x-3y+y-x) step three -2y(2x-4y) final step -2y(x-2y) I know this is incorrect, I just need some help identifying what I am missing. Thanks

Thank you MarkFL and Evinda, I'm only in grade 5 so I apologize if my questions are simplistic. I am just starting to learn factoring. I was told the answer is -(2x-y-z)(y-z) leading with the negative. Why is your answer different? If they are both correct, what did they do...

Hi, I am new to factorization. Would someone please solve these two equations and explain step by step what was done. thanks1. (x-y)^2 - (x-z)^2 = 2. (5x+2)^2 - (3x-4)^2 =