Recent content by risphysics

Thanks so much ... you have simplified it for me to understand now.

(1) a = bxh (2) a = 1/2 bxh (3) AB^2 = AB^2 + (AB)^2 (4) = nr^2 (circ / diam) (5) Not 100% sure on finding perimter of cirlce Thanks for taking the time Maze.

No I haven't learned the method of breaking it up into pieces. Could you elaborate further pls. I'm studying Residential Drafting via correspondece, so unfortunately I do not have a teacher to refer to. Thanks again.

I'm a new student to complex maths & I'm after the formula to calculate the exterior surface area of the prism - see attached diagram. I know formula for a surface area of triangular prism = ab + ph and cylinder = 2pir^2 + 2 pi rh. Don't know where/how to apply formula to half of these...