Okay,
so I'm meant to use the equation twice.
In that case,
f obs (police) = fs (( vw + vobs) / (vw + vs ) )
I keep fs = 4.3kHz and as both sources are still going towards each other (+)
vw = 340 m/s
V obs (detector) = v = fλ = 4,300 * 0.044 = 189.2 km/h (?) (52.56 m/s)
Vs = 64...