Recent content by robertsa

Well i found the new volume first using Change V/V= linear expansion coeffecient(change tmp)... orginal v =125cm3...Delta V/125=17x10^-6 x 50... Change V=.31875 so the new volume is 125.31875cm^3... but I don't know how to find the new density..d=m/v... would mass not change even though the...

Homework Statement if the original density of a cube is 869 kg/m3 and volume 125cm3.. the cube is is heated to a new volume of 125.00255cm3 what's the new density

The calculation i did above was for when he was standing upright.. when he is upside down the pressure in the brain should be greater than that of the presure in the feet.

We did the solution for the same height, when standing upright in class. We always to the distance to be from the heart..im just not sure how to approach when he's upside down.

Homework Statement a person is 1.8 m tall, standing upright. His heart is 1.4m above his feet. He is doing a head stand. Calculate the hydrostatic blood pressure in (a) his feet and (b) his head. Homework Equations P-Po= density x g x d The Attempt at a Solution When...

Homework Statement A mountaineer in the Rockies measures the air pressure to be 10% below that at sea level. At what height above sea level does he make the measurement? At this altitude he finds a small mountain lake of fresh water which is 4.3m deep at its deepest point. What is the...

Soo. 1m^3=1025 kg 3m^3=1025 x 3=3075kg 1kg=0.001metric tonns 3075 x 0.001 =3.075 metric tonnes its really that simple? haha

Homework Statement Fossilized ichthyosaurus remains enable us to estimate their volume. If we assume that a 3m^3 icthyosaurus was "wightless" when it swam under water. What was its weight in metric tonnes? plugging this into the equation would give me B .. not weight...

Homework Statement Fossilized ichthyosaurus remains enable us to estimate their volume. If we assume that a 3m^3 icthyosaurus was "wightless" when it swam under water. What was its weight in metric tonnes? Homework Equations B=Wdisp. lqd ?? The Attempt at a Solution B=V x...

Homework Statement There are 3.344 x 10^25 molecules in 1 kg (1 litre) of water. What is the distance between the molecules? Homework Equations The Attempt at a Solution I found the density of water in kg/m^3, then found # moles in 1 litre (55.6) and then from that using Na I...