Recent content by RobotGymnast

That's what I got. What confuses me was that I also got a different answer by substituting physics equations into one another. I ended up getting ¼ Jt^3 rather than 1/6 Jt^3. But integrating the equation for jerk motion twice gives the answer you gave, which I think is correct.

*jerk motion (the derivative of acceleration). whoops.

Kinematics. As in, delta d = vt + (1/2)at2 except assuming that jerk motion is constant, rather than acceleration.

What formula would one use to solve for delta d with regards to t, v1, a1, and constant J?