Recent content by Rookiemonster

Are you are a hero. I hadn't thought to use the probability of coefficients.

so the bra-ket of \varphi_{1} and \varphi_{2} should be equal to zero. Therefore, either \varphi_{1} or \varphi_{2} needs to be zero in total. Therefore, \chi_{1}=3 and \chi_{2}=-2 or \chi_{1}=2 \chi_{2}=3 The problem is putting these values into a squared bra-ket of \varphi_{1}...

This is the sort of thing that should be easy but my brain has blanked due to be overloaded in other areas of Physics. I've tried a great deal of different approaches but I'll walk though the one that led closest. I assumed that \hat{A} and \check{B} where both hermitian so there...