Recent content by rozma3

What would be the next step? Really sorry but I struggle quite heavily with these sorts of questions.

6 hours?

Good effort though! You have omega, the formula you want to be using is a = w^2 r substituting w = v/r into the original formula you have.

I see. So in the calculation, the LST will be 5 hours 27 minutes. Then the right ascension being 18 hours. 5h 27 m - 18h = 12h 33 minutes, correct?

Rotating 15 degrees, but how does that affect the LST. Does it mean it becomes 7h 27m?

Thank you for your reply. I am not entirely certain about how exactly to take into account the 1 hour time difference between 00:00 and 23:00.

I believe it is the fact that when you use the dot product with two vectors, you end up with a scalar value or along that principle but not entirely certain. The calculation a.b = mag a x mag b x cos ab, so no vectors involved.

Homework Statement At midnight (local time) on Dec 21st 2015, the Local Sidereal Time at Palomar Observatory, California, was 6h 27m. Palomar Observatory has latitude 33◦ 210 2100 N, and longitude 116deg 51arcmin 60arcsecW. a) What was the approximate Local Hour Angle of the Sun at 23:00 local...