Recent content by rpg711

Here's the correct setup

Nope, the string is connected in such a way that it is parallel to the HORIZONTAL, so it makes an angle of 25 degrees with the incline. So there is a component parallel to the incline(Tcos(25)) and a component perpendicular to the incline that has to be factored into Friction/Normal force...

Yep, and determined that the only two forces acting UP the incline is friction and tension force(the parallel X component), and also that there is a Y component of tension perpendicular to the slope that would increase the normal force, which would increase the friction, which would reduce the...

Homework Statement A block with mass m1 = 9.2 kg is on an incline with an angle θ = 25.0° with respect to the horizontal. For the first question there is no friction between the incline and the block. The coefficient of static friction was deterimined to be μ = .121 The premise of this...