gneill
Thanks for your quick reply! Norton is another solution, however I want to see where I am blinding myself here.
OK, superposition, starting from below:
Z1(3Ohms) = 3Δ0o
Z2(5Ohms) = 5Δ0o
Z3(1Ohms) = 1Δ0o
Z4(L) = 2∏*50*0.05Δ90o
From the source below, the current through 1 Ohm should...