Recent content by rygza

I actually did try dividing them but then didn't know what to do from there. Thanks, this was of much help

I thought it was obvious that it does hold for all M,L, & T. If there were fixed values for them I would have included that information haha. You addressed the question but I stated that it wasn't straight forward. I already know what to do if there were fixed values (that's why I asked about...

You obviously understood what i meant. yes i know i didn't express everything in standard form and i did make a mistake with the first equation (now fixed). I didn't see the need, as equating the exponents would make it clear what i meant (which it seems it did to you). Regarding my actual...

so i need to find a,b, and c: (M^0)*(L^0)*(T^1) = (M^a+b+c)*(L^-a-3b+2c)*(T^-2a-2c) to solve i equated the exponents to that of each matching variable: a+b+c = 0 -a-3b+2c = 0 -2a-2c = 1 Is there a mathematical process of obtaining the above equations besides simply "equating" the...

ah ok, thank you!

so I'm graphing tetrahedron bounded by a given plane and "The coordinate planes" what is meant by "the coordinate planes"? i can graph the plane but i need help here

When do i know which component of velocity to use when an object is shot at an angle? For example: a ball of given mass is shot 32degrees above the ground with Vinitial of 74m/s. In using conservation of energy, K.E. = .5 mv^2 , which velocity component do i use?

My instructor told the class to keep in mind that we should only account for normal force when friction is involved in the problem. In my book there is a problem in which friction is negligible and they account for normal force, but ultimately the normal force has no effect on the conclusion of...

OOH yes now it makes sense :smile: I miss one little thing and it costs me 30minutes lol THANK YOU!

but wouldn't delta x be the length of the bottom side? and then the hypotenuse would be = sqrt((delta x)^2 + (h)^2)

In the attached picture there is a right triangle (the right angle is on the right bottom corner). The angle, theta, is on the left-most side. From what i remember, sin (theta) is equal to opposite/hypotenuse. If you can see in the picture, it has written: delta x = h/sin(theta) so...

y=1/2(sinx-cosx+e(^pi-x)) question: if x approaches infinity, which term or terms will dominate? from my understanding, sinx and cosx will oscillate and the e term will approach zero. so would the answer be sinx-cosx? please and ty

thanks!

Undetermined Coefficients, just a piece i need help with please In one of the last steps in trying to find the Coefficients of Yp (particular solution), I am supposed to set coefficients of similar terms equal to each other. Here's where i need help: i have A(e^x) + (-2B-2C+2F+E)sinx +...

sooo sorry. I've been reading the problem over and over (it's actually a mass on spring problem). It uses the term "from rest", meaning initial velocity is 0. Now when i solve for the constants i get 0 = 16C1 and C1 = 0 Wow, an hour wasted because i missed that part