Recent content by s.bala

check my numbers please: [(8.99x10^-12)(-16x10^-9)(45.5x10^-9)]/0.57^2 =-0.000020143 i beleieve it comes out to be negative because charge1 is given as -16nC

this was due last week lol..ive learned the answer and the theroy behind it...its actually will oppose it

in terms of magnitude i get -0.000020143 and positive 0.000013501 if u consider the vecetors u would get positive 6.64*10^-6...im doing this for an online test at uft and I've treid the negative value for that and its wrong..i have only one chance left to answer it and the question says your...

well, since the charge1 is negative and is on the leftside of charge3, and charge2 is positive and on the rightside of charge 3, charge 1 will exert a pull force and charge 2 will exert a push force.. so the force directions should both be to the left if I am not mistaken..ps ty for the reply

i keep getting this question wrong can some1 help -------------------------------------------------------------------------------- two point charges located on the x axis: one charge, q1 = -16.0 , is located at x1= -1.650m ; the second charge, q2= 38.5nC , is at the origin x=0. A 3rd...

i keep getting this question wrong can some1 help -------------------------------------------------------------------------------- two point charges located on the x axis: one charge, q1 = -16.0 , is located at x1= -1.650m ; the second charge, q2= 38.5nC , is at the origin x=0. A 3rd...

initally there's a electric field pointing to the right near a rod...something happens and the rod becomes negative on leftside on positive on rightside whihc supposedly generate another electric field near the rod..does this new one oppose the other one in terms of direction or make it stronger?