So is my free body diagram referring to the case correct?
[shown in attached document]
Even though the normal force is not evenly exerted on the block, the total normal force exerted on the block is still mgcos(A). And the net normal force should not act through the centre of mass of the...
Sorry...can you further explain the above sentence, I don't understand why there is no net torque when the coefficient is the same at all points of contact.
A block of mass m is on a frictionless inclined plane with no initial speed.
The net force which equals to the component of the block's weight along the inclined plane, acted through the block's centre of mass, so there is no torque acted on the block, so the block does not rotate and just...